You add 400 mL of water at 30C to 100 mL of water at 80C. What is the most likely final temperature of the mixture? A. 110C B. 50C C. 20C D. 40C

Problem: What is the most likely final temperature of the mixture

Given: m1 = 400ml m2=100ml

c1 = 4.18J/g∘C (specific heat of water) c2=4.18J/g∘C

T1=30C T2=80C

Solution: Formula: T = (m1c1T1 + m2c2T2) / (m1c1 + m2c2)

[ (400) (4.18) (30) + (100) (4,18) (80) ] / [ (400) (4.18) + (100) (4.18) ]

=[ (50,160) + (33,440) ] / [ (1672) + (418) ]

=83,600/2090

Answer = 40C