Problem 2.26 MasteringPhysics 10 of 16 Problem 2.26 When striking, the pike, a predatory fish, can accelerate from rest to a speed of 3.9 m/s in 0.11 s Part B How far does the pike move during this strike?.

final velocity = initial velocity + (acceleration x time)

3.9 m/s = 0 m/s + (acceleration x 0.11 s)

3.9 m/s / 0.11 s = acceleration

30.45 m/s^2 = acceleration

distance = (initial velocity x time) + 1/2 (acceleration) (time^2)

distance (0 m/s x 0.11 s) + 1/2 (30.45 m/s^2) (0.11s ^2)

distance = 0.18 m