Ask Question
10 September, 07:14

Suppose you were marooned on a tropical island and had to use seawater (density 1.10 g·cm3) to make a primitive barometer. what height would the water reach in your barometer when a mercury barometer would reach 73.5 cm? the density of mercury is 13.6 g·cm3

+5
Answers (1)
  1. 10 September, 10:43
    0
    We know that P = hρg

    Where:

    P - pressure Pa,

    h - height in meter,

    ρ - would be the density in kg / m^3; and

    g - acceleration due to gravity is m / s^2

    p = hρg if h = 0.735 meter, ρ = 13600 kg / meter^3, g = 10 meter / sec^2

    p = 0.735*13600*10 = 99960 Pa or

    P = 1 x 10^5 Pa

    Now with sea water if we have to make a barometer:

    ρ = 1100 kg / meter^3 (given)

    P = hρg if we put the value of P calculated and the value of ρ = 1100 kg / meter^3 given, we will

    get, 1 x 10^5 = h*1100*10

    therefore, h = 9.09 meter or 29.82 feet of water.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose you were marooned on a tropical island and had to use seawater (density 1.10 g·cm3) to make a primitive barometer. what height ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers