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14 December, 01:46

You throw a 20-n rock vertically into the air from ground level. you observe that when it is a height 16.0 m above the ground, it is traveling at a speed of 24.7 m/s upward.

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  1. 14 December, 04:15
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    The problem is missing some parts. But here are the questions and answers.

    a. Use the work-energy theorem to find its speed just as it left the ground

    Initial Kinetic Energy = GPE + KE

    1/2 * m * V^2 = m * g * h + 1/2 * m * v^2

    V^2 = 2 * 9.8 * 15.6 + 25.6^2

    =sqrt 968.96

    V (initial speed) ≈ 31.130 m/s

    b. Use the work-energy theorem to look for its maximum height.

    H = 968.96 / 2 * 9.8 ≈ 49.44 m
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