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24 June, 19:23

10. A cruise ship travels directly toward the dock at a speed of 12 m/s. A passenger walks 2 m/s in the same direction as the ship travels. After three seconds, the distance from the passenger to the dock has decreased by -

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  1. 24 June, 20:49
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    To be very technical about it ... you didn't say what the reference is for the passenger's "2 m/s". Is that relative to the ship, or relative to the dock?

    In fact, you didn't tell us the reference for the ship's "12 m/s" either.

    I think I know how you meant it all, and if I'm correct, you actually switched

    reference frames during the question and didn't tell us.

    I have a hunch that the ship is moving at 12 m/s relative to the dock, and the

    passenger is walking at 2 m/s relative to the ship.

    That means that the passenger is moving at (12 + 2) = 14 m/s relative to

    the dock, and after doing this for 3 seconds, he is 42 meters closer to the

    dock than he was when the story began.

    That's the sum of (12 x 3) = 36 meters that the ship has carried him

    relative to the dock, plus the (2 x 3) = 6 meters that he has walked

    along the deck of the ship.
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