Ask Question
24 October, 19:21

A meteorite approaching a planet of mass M collides with an automatic space station orbiting the planet in a circular trajectory of radius R. The mass of the station is ten times as large as the mass of the meteorite. As a result of the collision, the meteorite sticks with the station which goes over to a new orbit with the minimum distance R/2 from the planet. Speed of the meteorite just before it collides with the space station is

+3
Answers (1)
  1. 24 October, 23:19
    0
    We are given with

    M = mass of planet

    R = radius of circular trajectory of the satellite

    ms = mass of the station

    mm = mass of the meteorite

    ms = 10 mm

    R/2 = new orbit distance

    The speed of the meteorite can be solved using the law of conservation of momentum

    ms vs + mm vm = (ms + mm) v

    Since the new orbit distance is half the original

    v = 2 vs

    Substitute and solve for vs
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A meteorite approaching a planet of mass M collides with an automatic space station orbiting the planet in a circular trajectory of radius ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers