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2 April, 02:07

If the change in enthalpy is - 5074.1 kj, how much work is done during the combustion?

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  1. 2 April, 02:33
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    Hence,

    ∆H = ∆U + W

    =>

    W = ∆H - ∆U

    = - 5074 kJ - (-5084.) kJ

    = 10 kJ
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