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7 September, 02:41

From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of - 9.0 meters/second. After 0.50 seconds, how far beneath the cliff is the pebble?

a) - 2.0

b) - 3.9

c) - 5.7

d) - 10.3

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  1. 7 September, 04:18
    0
    Y - yo = Vo*t - g * (t^2) / 2

    Vo = - 9.0 m/s

    t = 0.50 s

    => y - yo = - 9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s) ^2 / 2 = - 4.5m - 1.225m = - 5.725 m.

    Answer: option c) - 5.7
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