Ask Question
31 March, 02:55

An 18-mm-wide diffraction grating has rulings of 710 lines per millimeter. monochromatic light of wavelength 506 nm wavelength is incident normally on the grating. what is the largest angle from the centerline at which an intensity maximum is formed?

+4
Answers (1)
  1. 31 March, 04:32
    0
    W = 18*10^-3m

    N = 18*710 (because you have 710 slits per mm) = 12780

    lambda = 506*10^-9

    The first step is to workout d.

    d = w/N

    d = 18*10^-3m/12780

    d = 1.41*10^-6m

    The second step is to work out the maximum number of m.

    Since sin (theta) = less than 1, then m*lambda/d = less then 1,

    therefore m = less than d/lambda

    (I know thats confusing but trust me)

    so m is less than 1.41*10^-6m/506*10^-9

    = 2.7

    Therefore use m = 2

    Lastly put it all into the formula

    dsin (theta) = m*lambda so:

    theta = sin^-1 (m*lambda/d)

    theta = sin^-1 (2*506*10^-9/1.41*10^-6m)

    theta = 45.95 degrees or 46 degrees
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “An 18-mm-wide diffraction grating has rulings of 710 lines per millimeter. monochromatic light of wavelength 506 nm wavelength is incident ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers