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27 March, 16:30

What is the mass in grams of 0.338 mol of glucose (C6H12O6) ? step by step

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  1. 27 March, 18:44
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    The amount in mole of a substance = mass in gram * (1 mole of the substance / molar mass of the substance).

    molar mass of C6H12O6 = (12*6) + (1*12) + (16*6) = 180.

    Let the mass of glucose in gram = G

    0.338 = G X (I/180)

    0.338 = G/180

    G = 0.338 X 180 = 60.84g.
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