A hot iron ball of mass 200 g is cooled to a temperature of 22°C. 6.9 kJ of heat is lost to the surroundings during the process. What was the initial temperature of the ball? (ciron = 0.444 J/g°C)

A)

23°C

B)

78°C

C)

100°C

D)

155°C

Question

Physics

Sierra

27 November, 03:01

A hot iron ball of mass 200 g is cooled to a temperature of 22°C. 6.9 kJ of heat is lost to the surroundings during the process. What was the initial temperature of the ball? (ciron = 0.444 J/g°C)

A)

23°C

B)

78°C

C)

100°C

D)

155°C

+2

Answers (1)

Know the Answer?

Aleena Andrade · Answer 1

Heat lost or gained, H = mc (θ₂ - θ₁)

Where m = mass, c = Specific heat capacity, θ₂ = final temperature, θ₁ = initial temperature

m = 200g, c = 0.444 J/g°C, θ₁ = 22 °C (Since it was cooled).

H = 6.9 kj = 6.9 * 1000J = 6900 J

6900 = 200*0.444 * (θ₂ - 22)

6900 / (200*0.444) = θ₂ - 22

77.70 = θ₂ - 22

θ₂ - 22 = 77.7

θ₂ = 77.7 + 22 = 99.7

So initial temperature before cooling ≈ 100°C. Option C.

A hot iron ball of mass 200 g is cooled to a temperature of 22°C. 6.9 kJ of heat is lost to the surroundings during the process. What was the initial temperature of the ball? (ciron = 0.444 J/g°C)A)23°CB)78°CC)100°CD)155°C

A hot iron ball of mass 200 g is cooled to a temperature of 22°C. 6.9 kJ of heat is lost to the surroundings during the process. What was the initial temperature of the ball? (ciron = 0.444 J/g°C)

A)

23°C

B)

78°C

C)

100°C

D)

155°C