An aluminum rod and a nickel rod are both 5.00 m long at 20.0 degree Celsius. The temperature of each is raised to 70.0 degrees Celsius. What is the difference in length between the two rods (Unit=m) ?

0.002925 m

Explanation:

Lt = LO (1 + α Δt) here Lt is total length Lo is original length α is coefficient of linear expansion and Δt is change in temperature

for aluminium

α=25*10^-6

Lt = 5 (1+25*10^-6 * (70-20))

Lt = 5 (1+25*10^-6*50)

Lt = 5 (1+0.00125)

Lt = 5*1.00125

Lt = 5.00625 m

for nickel

α=13.3*10^-6

Lt = 5 (1+13.3*10^-6*50)

Lt = 5 (1+0.000665)

Lt = 5.003325 m

hence difference in length = 5.00625-5.003325

= 0.002925 m