A wire carrying a 2-A current is placed at an angle of 60° with the respect to a magnetic field of strength 0.2 T. If the length of the wire is 0.6 m what is the magnitude of the magnetic force acting on the wire?

0.208 N

Explanation:

Parameters given:

Current, I = 2A

Angle, A = 60°

Magnetic field strength, B = 0.2 T

Length, L = 0.6 m

Magnetic force is given as:

F = I * L * B * sinA

F = 2 * 0.6 * 0.2 * sin60

F = 0.24 * sin60.

F = 0.208 N

0.20784 N

Explanation:

The force on conductor carrying current in a magnetic Field is given as,

F = BILsinθ ... Equation 1

Where F = force on wire carrying current, B = magnetic Field, I = current, L = Length of the wire, θ = angle between the wire and the magnetic Field.

Given: B = 0.2 T, I = 2 A, L = 0.6 m, θ = 60°

Substitute into equation 1

F = 0.2 (2) (0.6) sin60°

F = 0.24*0.8660

F = 0.20784 N