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11 November, 12:27

How many joules are released as 10.0g of steam at 110℃ cools to produce water at 25℃?

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  1. 11 November, 15:17
    0
    26,000 J

    Explanation:

    Heat released when the steam is cooled:

    q = mCΔT

    q = (10.0 g) (2.02 J/g/K) (100℃ - 110℃)

    q = - 202 J

    Heat released during condensation (gas to liquid):

    q = mL

    q = (10.0 g) (-2260 J/g)

    q = - 22,600 J

    Heat released when the liquid water is cooled:

    q = mCΔT

    q = (10.0 g) (4.184 J/g/K) (25℃ - 100℃)

    q = - 3138 J

    Total heat released:

    q = - 202 J - 22,600 J - 3138 J

    q = 25,940 J

    Rounded to two significant figures, 26,000 J of heat are released.
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