Ask Question
28 April, 09:23

A merry-go-round is a common piece of playground equipment. A 3.0-m-diameter merry-go-round, which can be modeled as a disk with a mass of 300 kg, is spinning at 25 rpm. John runs tangent to the merry-go-round at 5.8 m/s, in the same direction that it is turning, and jumps onto the outer edge. John's mass is 30 kg.

+1
Answers (1)
  1. 28 April, 12:46
    0
    w2 = 2.83 rad/s

    Explanation:

    The moment of inertia of the merry-go-round is

    I = (1/2) M R^2

    I = 1/2 * 300 kg * 1.5 m^2

    I = 337.5 kg*m^2

    The initial angular velocity of the merry-go-round is

    w1 = 25 rpm * 2*pi / 60

    w1 = 2.6 rad/s

    The angular momentum conservation equation is:

    I*w1 + m*R*v = (I + mR^2) * w2

    where m is John's mass.

    337.5*2.6 + 30*1.5*2.6 = (337.5 + 30 * (1.5) ^2)

    887.5 + 261 = (337.5 + 67.5) * w2

    w2 = 2.83 rad/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A merry-go-round is a common piece of playground equipment. A 3.0-m-diameter merry-go-round, which can be modeled as a disk with a mass of ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers