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27 September, 03:51

An 80-kgkg quarterback jumps straight up in the air right before throwing a 0.43-kgkg football horizontally at 15 m/sm/s. How fast will he be moving backward just after releasing the ball?

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  1. 27 September, 05:17
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    V = 0.0806 m/s

    Explanation:

    given data

    mass quarterback = 80 kg

    mass football = 0.43 kg

    velocity = 15 m/s

    solution

    we consider here momentum conservation is in horizontal direction.

    so that here no initial momentum of the quarterback

    so that final momentum of the system will be 0

    so we can say

    M (quarterback) * V = m (football) * v (football) ... 1

    put here value we get

    80 * V = 0.43 * 15

    V = 0.0806 m/s
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