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28 February, 03:59

The magnitudes of the vertical and horizontal components of a vector are 11 and 17 centimeters respectively. Find the magnitude of the vector and the angle from the horizontal axis.

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  1. 28 February, 04:40
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    let the magnitude of the vector be |A|

    |A| = ✓11^2 + 17^2 =

    |A| = ✓410

    |A| = 20.23

    theta = Tan^-1 (11/17) = 32.91°
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