Two brothers push on a box from opposite directions. If one brother pushes with a force of 86 N and the other brother pushes with a force of 67 N, what is the magnitude of the net force on the box? A. 67 N * sin (86°) B. 86 N - 67 N C. ([86 N]2 + [67 N]2) 1/2 D. 86 N/cos (67°)

Question

Physics

Zain

2 March, 20:46

Two brothers push on a box from opposite directions. If one brother pushes with a force of 86 N and the other brother pushes with a force of 67 N, what is the magnitude of the net force on the box? A. 67 N * sin (86°) B. 86 N - 67 N C. ([86 N]2 + [67 N]2) 1/2 D. 86 N/cos (67°)

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Answers (2)

Know the Answer?

Violet · Answer 1

The correct answer is B) i took the test and got it correct

Armani Burch · Answer 2

Choose B.

The 2nd brother's 67N cancels 67 of the first brother's 86N. But that still leaves the first brother with 19 good Newtons, so he wins the push-o-war.