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24 February, 17:07

Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is three times the heat capacity of Object B and the initial temperature of Object A (TA) is twice the initial temperature of Object B (TB).

1)

What will the final temperature of the two-object system be?

2TB

1.75TB

1.5TB

1.2TB

TB

+3
Answers (1)
  1. 24 February, 20:20
    0
    Heat capacity A = 3 x heat capacity of B

    initial temperature of A = 2 x initial temperature of B

    TA = 2 TB

    Let T be the final temperature of the system

    Heat lost by A is equal to the heat gained by B

    mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x (T - TB)

    heat capacity of A x (TA - T) = heat capacity of B x (T - TB)

    3 x heat capacity of B x (TA - T) = heat capacity of B x (T - TB)

    3 TA - 3 T = T - TB

    6 TB + TB = 4 T

    T = 1.75 TB
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