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28 February, 23:40

If a ball is given a push so that it has an initial velocity of 5 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation. s (t) = 5t + 2t2 (a) Find the velocity after 2 seconds.

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  1. 1 March, 02:12
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    v = 13 m/s

    Explanation:

    Velocity is defined as the derivative of displacement with respect to time

    v = ds/dt

    Known data

    s (t) = 5t + 2t² : distance that the ball has rolled after t seconds

    vi = 5 m/s : initial velocity

    t = 2 s

    Problem develoment

    s (t) = 5t + 2t²

    v = ds/dt = 5 + 4t : velocity of the ball in function of the time

    We replace t = 2 s in the equation of velocity

    v = 5 + 4 (2)

    v = 13 m/s : velocity after 2 seconds
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