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31 December, 01:32

An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster.

If her velocity increases to 5 m/s, what is her change in kinetic energy as a result?

J

How much work did she perform?

J

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Answers (1)
  1. 31 December, 02:40
    0
    640 J

    640 J

    Explanation:

    ΔKE = ½ mv² - ½ mu²

    ΔKE = ½ m (v² - u²)

    ΔKE = ½ (80 kg) ((5 m/s) ² - (3 m/s) ²)

    ΔKE = 640 J

    Work = ΔE

    Work = 640 J
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