If a 1-megaton nuclear weapon is exploded

at ground level, the peak overpressure (that

is, the pressure increase above normal atmospheric pressure) will be 0.2 atm at a

distance of 6 km. Atmospheric pressure is

1.013 * 10^5 Pa.

What force due to such an explosion will be

exerted on the side of a house with dimensions

3.89 m * 22.6 m?

Answer in units of N

Question

Niko Chen

24 February, 02:31

+5

Answers (1)

Know the Answer?

Damarion · Answer 1

1,780,000 N

Explanation:

0.2 atm * (1.013*10⁵ Pa/atm) = 20,260 Pa

Force = pressure * area

F = 20,260 Pa * (3.89 m * 22.6 m)

F = 1,780,000 N