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20 April, 14:20

What is the mass of a bullet moving at 970m/s if the bullet's KE is 3.9x 10^3J

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Answers (2)
  1. 20 April, 15:16
    0
    I think the Answer is 0.08kg
  2. 20 April, 15:30
    0
    0.08kg

    Explanation:

    K. E = 1/2 mv^2

    v = 970m/s

    K. E = 3.9x 10^3J = 3900J

    K. E = 1/2 mv^2

    3900 = 1/2 m x 970x 970

    3900 = 1/2 * 940900m

    3900 = 470450m

    m = 3900/470450 = 0.00828993516 = 0.008kg
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