A ball is thrown into the air with an initial velocity of 15 m/s, how high into the air does the ball travel?

11.25m

Explanation:

vf^2=vi^2+2ad

0^2=15^2+2 * (-10) d

0=225+-20d (remove 225 by doing the opposite operation)

-225:-20=-20d:-20 (remove - 20 by dividing by itself)

11.25 = d (the answer becomes this)