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5 April, 23:36

A bowling ball is dropped from a height of 24 feet.

a. Write a function that gives the height h (in feet) of the bowling ball after t seconds. h (t) = ?

b. Find the height of the bowling ball after 1 second. The height of the ball after 1 second is feet.

c. How long does the bowling ball take to hit the ground? Round your answer to the nearest hundredth of a second. The bowling ball takes about __ seconds to hit the ground.

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  1. 6 April, 01:32
    0
    a. H = (1/2) * a*t^2

    B. h=16.09ft

    C. t = 1.22s

    Explanation:

    Explanation: Newton's equation of motion. This is called motion under free fall.

    S=ut + (1/2) * a*t^2

    Let S=H, and a=g

    1.

    H=ut + (1/2) * g*t^2

    H=distance covered in ft (24ft)

    u = initial velocity (ft/s)

    t = time covered in seconds

    g=acceleration due to gravity (ft/s^2)

    a=g (32.185ft/s)

    When u=0

    H = (1/2) * g*t^2

    2. H = (1/2) * g*t^2

    g=32.185ft/s^2

    t=1s

    Juxtaposing the values into the equation

    H = (1/2) * 32.185 * (1) ^2

    H=16.09ft

    3. When the maximum distance covered is 24ft, then using

    H = (1/2) * a*t^2

    24=0.5*32.165*t^2

    24=16.09t^2

    1.491=t^2

    Find the square root of both sides

    t=1.22s

    It takes 1.22s to hit the ground
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