a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0 degree angle, against a 14.2 N friction force. find the work done by the friction force

a. - 191.7 J

Explanation:

The work done by a force is given by W = Fdcosθ where F = force applied and d = distance moved and θ is the angle between the force and distance moved.

Here, F = frictional force = 14.2 N

d = distance = 13.5 m

and θ = 180° since the direction of the frictional force and distance are opposite.

So, W = Fdcosθ = 14.2 * 13.5cos180° = - 191.7 J