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24 January, 08:41

The frequency of the 15. ocm string is how many times higher than the frequency of the 30.0cm string

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  1. 24 January, 09:14
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    2 times.

    Explanation:

    We know that f = V / λ ... (1)

    λ (a) = 15 cm

    λ (b) = 30 cm

    Va=Vb

    Now by using the above formula;

    f_{a} = Va/15 = Va = 15*f_{a}

    f_{b} = Vb/30 = Vb = 30*f_{b}

    As, Va = Vb

    15*f_{a} = 30*f_{b}

    f_{a} / f_{b} = 30/15

    = 2 times
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