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20 October, 17:01

Ben starts walking along a path at 3 3 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 6 6 mi/h. How long will it be before Amanda catches up to Ben?

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  1. 20 October, 19:24
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    3 hours

    Explanation:

    Given:

    - The speed of Ben v_b = 3 mi/h

    - The speed of Amanda v_a = 6 mi/h

    - The total time taken to cover distance (d) by ben = t_b

    Find:

    How long will it be before Amanda catches up to Ben?

    Solution:

    - The distance d traveled by Ben:

    d = v_b*t_b

    d = 3*t_b

    - The distance d traveled by Amanda:

    d = v_a*t_a

    d = 6*t_a

    - Equate the distance as when they meet:

    3*t_b = 6*t_a

    - Where,

    t_b = t_a + 1.5

    t_a = t_b - 1.5

    - Substitute the time relationship in distance relationship:

    3*t_b = 6 * (t_b - 1.5)

    3*t_b = 6*1.5

    t_b = 2*1.5 = 3 h

    - Hence, It would take 3 hours since Ben starts walking that amanda catches up.
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