The length of a retanle is twice the width plus 10. if the perimenter of the rectangle must be 200 inches what is the maimumarea of the rectange?

Area = 2100 inch²

Explanation:

The length of a rectangle is twice the width plus 10

Let L be the length and W be the width.

L = 2W + 10

The perimeter of the rectangle must be 200 inches

Perimeter = 2 (L+W) = 200

2 (2W+10+W) = 200

3W + 10 = 100

3W = 90

W = 30 inches

L = 2 x 30 + 10 = 70 inches

Area = Length x Width

Area = 30 x 70

Area = 2100 inch²