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10 January, 22:28

A 0.25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. What is the final velocity of the combined mass

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  1. 10 January, 23:49
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    Answer:20/47 meter per second

    Explanation:

    Mass of arrow (ma) = 0.25kg

    Velocity of arrow (va) = 12m/s

    Mass of target (mt) = 6.8kg

    Velocity of target (vt) = 0 since target is at rest

    Conservation of linear momentum says that:

    maxva+mtxvt = (ma+mt) V

    V = (maxva+mtxvt) / (ma+mt)

    V = (0.25x12+6.8x0) / (0.25+6.8)

    V=3 / (7.05)

    V=20/47 meter per second
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