A child of mass 49.7 kg sits on the edge of a merry-go-round with radius 2.7 m and moment of inertia 311.589 kg m2. The merrygo-round rotates with an angular velocity of 2.8 rad/s. What radial force does the child have to exert to stay on the merry-go-round? Answer in units of N.

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Physics

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15 September, 05:52

A child of mass 49.7 kg sits on the edge of a merry-go-round with radius 2.7 m and moment of inertia 311.589 kg m2. The merrygo-round rotates with an angular velocity of 2.8 rad/s. What radial force does the child have to exert to stay on the merry-go-round? Answer in units of N.

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Answers (1)

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Katie Velez · Answer 1

The radial force is F_c = 1052.04 N

Explanation:

Given to find the radial force

m = 49.7 kg

r1 = 2.7 m

I = 311.589 kg*m^2

ω = 2.8 rad/s

F_c = m*r1 * ω²

To find the angular force to stay on the merry go round

so replacing numeric:

F_c = 49.7 kg * 2.7m * (2.8 rad/s ^2)

F_c = 1052.04 N