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2 September, 12:24

6) A person with mass 50.0 kg, standing still, throws an object with mass 12.0

kg. If the velocity of the person after throwing is + 2.0 m/s, what is the

velocity at which he threw the object? Assume the surface to be frictionless.

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Answers (1)
  1. 2 September, 15:04
    0
    Momentum before = momentum after

    m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

    (50.0 kg) (0 m/s) + (12.0 kg) (0 m/s) = (50.0 kg) (2.0 m/s) + (12.0 kg) v

    v = - 8.33 m/s
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