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3 June, 13:41

10) A bowling ball released from rest at the top of a 200. m building falls to the ground under the influ-

ence of gravity. Calculate:

a) its speed at 5.00 s

b) how far it has gone when its speed is 32.0"

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Answers (1)
  1. 3 June, 15:30
    0
    Given:

    v₀ = 0 m/s

    a = 9.8 m/s²

    a) Find v when t = 5.00 s.

    v = at + v₀

    v = (9.8 m/s²) (5.00 s) + 0 m/s

    v = 49.0 m/s

    b) Find Δx when v = 32.0 m/s.

    v² = v₀² + 2aΔx

    (32.0 m/s) ² = (0 m/s) ² + 2 (9.8 m/s²) Δx

    Δx = 52.2 m
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