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24 July, 15:07

A straight, horizontal length of copper wire has a current i=28A through it. What are the magnitude and direction of the minimum magnetic field B needed to suspend the wire (to balance the gravitational force on it) if the linear density of the wire is 46.6g/m?

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  1. 24 July, 16:12
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    0.01631 T

    Explanation:

    current, i = 28 A

    mass per unit length, m/l = 46.6 g/m = 0.0466 kg/m

    Let the magnetic field is B.

    the weight of the wire is balanced by the magnetic force.

    mg = i l B

    B = mg / i l

    B = (m/l) x g/i

    B = 0.0466 x 9.8 / 28

    B = 0.01631 T

    Thus, the magnetic field is 0.01631 T.
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