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26 October, 19:20

The shock absorbers in a car act as a

big spring. When a 92.5 kg person

gets in, the car sinks 0.0131 m. What

is the spring constant of the shocks?

(Unit = N/m)

+2
Answers (1)
  1. 26 October, 23:04
    0
    6.92*10^4 N/m

    Explanation:

    F = kx

    => k = F/x and force F = weight = mg, so

    k = mg/x

    = (92.5*9.8) / 0.0131

    = 6.92*10^4 N/m
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