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27 August, 12:37

A cyclist rides down a long straight road at a velocity (in m/min) given by v (t) equals400minus20 t, for 0less than or equalstless than or equals10. a. How far does the cyclist travel in the first 6 min? b. How far does the cyclist travel in the first 10 min? c. How far has the cyclist traveled when his velocity is 290 m/min?

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  1. 27 August, 16:30
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    a. 2040 m

    b. 3000 m

    c. 1697.5 m

    Explanation:

    Given that:

    v (t) = 400 - 20t

    0 ≤ t ≤ 10

    We can get the formula for distance traveled by integrating the velocity, v (t), with respect to time:

    => s (t) = 400t - 10t²

    a. First 6 mins:

    t = 6 mins

    s (t) = 400 (6) - 10 (6) ²

    s (t) = 2400 - 360

    s (t) = 2040m

    b. First 10 mins:

    t = 10 mins

    s (t) = 400 (10) - 10 (10) ²

    s (t) = 4000 - 1000

    s (t) = 3000 m

    c. When v (t) = 290 m/mins

    We insert this into the v (t) equation so we can find time t.

    v (t) = 400 - 20t

    290 = 400 - 20 (t)

    20t = 400 - 290

    20t = 110

    t = 110/20 = 5.5 mins

    Now we insert that into the s (t) equation:

    s (t) = 400 (5.5) - 10 (5.5) ²

    s (t) = 2200 - 302.5

    s (t) = 1697.5 m
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