what is the minimum speed that evil knevil must mantain on his motorcycle in order to make it around the loop-de-loop at ceasar's palace if together he and his bike weigh 3050n and the radius of the track is 25m

Minimum speed = 15.65 m/s

Explanation:

Parameters given:

Weight = 3050N

Radius of loop-de-loop track = 25m

In order to make it round the loop-de-loop, the Evil Knevil must get to the top of the loop.

At the top of the loop, asides from the Centripetal force acting on Evil and his bike, the gravitational force acts on them, pulling them down.

Considering the centripetal force, we know that centripetal acceleration is given as:

a = (v^2) / r

At the top of the loop, a = g (acceleration due to gravity). Hence,

g = (v^2) / r

=> v^2 = g*r

v = √ (g*r)

v = √ (9.8 * 25)

v = √ (245)

v = 15.65 m/s

Hence, Evil Knevil must maintain a minimum speed of 15.65m/s to go round the loop-de-loop.