Ask Question
14 August, 03:37

While leaning out a window that is 5.70 m above the ground, you drop a 0.600-kg basketball to a friend at ground level. Your friend catches the ball at a height of 2.00 m above the ground. Determine the following.

(a) the amount of work done by the force of gravity on the ball

(b) the gravitational potential energy of the ball-Earth system, relative to the ground when it is released

(c) the gravitational potential energy of the ball-Earth system, relative to the ground when it is caught

(d) the ratio of the change (PEf - PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity

+1
Answers (1)
  1. 14 August, 07:16
    0
    a) 21.756 J

    b) 33.516 J

    c) 11.52 J

    d) - 1

    Explanation:

    Net fall in height of ball = 5.70-2.0 = 3.70 m

    a) work done by the force of gravity on the ball = Mg*h = 0.6*9.8*3.7 = 21.756 J

    b) gravitational potential energy of the ball-earth system, relative to the ground when it is released = 0.6*9.8*5.70 = 33.516 J (ans)

    c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught = 0.6*9.8*2 = 11.52 J

    d) ratio of the change (PE_f - PE_0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity = (11.52 - 33.51) / (21.756) ≅-1 (ans)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “While leaning out a window that is 5.70 m above the ground, you drop a 0.600-kg basketball to a friend at ground level. Your friend catches ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers