A ball is thrown in the air with a vertical velocity of 12 m/s.

(a.) How long does it take to get to the top of its flights?

(b.) What is the average velocity of the ball on the way to the top?

(c.) What is the displacement of the ball (how high dose it go) ?

The answer to the question is gonna be A

a) 1.22 s

b) 6 m/s

c) 7.35 m

Explanation:

Given:

v₀ = 12 m/s

a = - 9.8 m/s²

a) Find t when v = 0 m/s.

v = at + v₀

(0 m/s) = (-9.8 m/s²) t + (12 m/s)

t = 1.22 s

b) v_avg = ½ (v₀ + v)

v_avg = ½ (12 m/s + 0 m/s)

v_avg = 6 m/s

c) Find Δx.

v² = v₀² + 2aΔx

(0 m/s) ² = (12 m/s) ² + 2 (-9.8 m/s²) Δx

Δx = 7.35 m