With an average acceleration of â1.2 m/s², how long will it take a cyclist to bring a bicycle with an initial speed of 6.5 m/s to a complete stop?

5.42 s

Explanation:

Using the equation of motion,

v = u + at ... Equation 1,

Where v = Final velocity, u = initial velocity, a = acceleration, t = time.

Making t the subject of the equation,

t = (v-u) / a ... Equation 2

Note: When the the bicycle is brought to a complete stop, the final velocity of the bicycle is 0 m/s and the bicycle is decelerating.

Given: v = 0 m/s, u = 6.5 m/s, a = - 1.2 m/s² (decelerating).

Substituting into equation 2

t = (0-6.5) / -1.2

t = - 6.5/-1.2

t = 5.42 s.

Hence the time take for the cyclist to bring the bicycle to complete stop = 5.42 s