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24 May, 11:04

A ball is thrown straight up and reaches a maximum height of 35m. Using 9.8m/s squared as gravity, what was the initial speed of the ball?

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Answers (1)
  1. 24 May, 13:00
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    26.2 m/s

    Explanation:

    Given:

    v = 0 m/s

    Δy = 35 m

    a = - 9.8 m/s²

    Find: v₀

    v² = v₀² + 2aΔy

    (0 m/s) ² = v₀² + 2 (-9.8 m/s²) (35 m)

    v₀ = 26.2 m/s
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