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5 February, 10:59

an object is thrown into the air with an initial velocity of 12 meters per seconds from a platform that is raised 4 meters above the ground. how long will it take for the object to return to the ground?

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  1. 5 February, 13:06
    0
    1.52 seconds

    Explanation:

    Step 1: identity the given parameters

    Initial velocity (u) = 12m/s

    Height above ground (h1) = 4m

    Final velocity (V) = 0

    Step 2: calculate the height travelled by the object from 4m height (h2).

    V^2 = U^2 - 2gh

    0 = 12^2-2 (9.8*h)

    2 (9.8*h) = 12^2

    19.6*h = 144

    h = 144/19.6

    h = 7.347 m

    Total height above ground (ht) = 4m + 7.347m = 11.347m

    Step 3: calculate the time reach ground

    T = √ (2h/g)

    T = √ (2*11.347/9.8)

    T = √ (22.694/9.8)

    T = √2.316

    T = 1.52 seconds
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