In moving out of a dormitory at the end of the semester, a student does1.6*10^4Jof work. In the process, his internal energy decreases by4.2*10^4JDetermine each of the following quantities (including the algebraic sign) : (a) W, (b) ΔU, and (c) Q

W = 1.6 * 10⁴ J, ΔU = - 4.2 x 10⁴ J, Q = - 2.6 x 10⁴ J

Explanation:

given,

Work done by the student

W = 1.6 * 10⁴ J

decrease in internal energy

ΔU = - 4.2 x 10⁴ J

Using formula for heat

Q = W + ΔU

Q = 1.6 * 10⁴ J + ( - 4.2 x 10⁴ J)

Q = - 2.6 x 10⁴ J

Hence,

W = 1.6 * 10⁴ J, ΔU = - 4.2 x 10⁴ J, Q = - 2.6 x 10⁴ J