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22 April, 14:50

A particle moves along the x axis. It is intially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration - 0.320 m/s^2. Suppose it moves as a particle under constant acceleration for 4.50m/s^2. Find its position.

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  1. 22 April, 15:27
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    The position of the particle is - 2.34 m.

    Explanation:

    Hi there!

    The equation of position of a particle moving in a straight line with constant acceleration is the following:

    x = x0 + v0 · t + 1/2 · a · t²

    Where:

    x = position of the particle at a time t:

    x0 = initial position.

    v0 = initial velocity.

    t = time

    a = acceleration

    We have the following information:

    x0 = 0.270 m

    v0 = 0.140 m/s

    a = - 0.320 m/s²

    t = 4.50 s (In the question, where it says "4.50 m/s^2" it should say "4.50 s". I have looked on the web and have confirmed it).

    Then, we have all the needed data to calculate the position of the particle:

    x = x0 + v0 · t + 1/2 · a · t²

    x = 0.270 m + 0.140 m/s · 4.50 s - 1/2 · 0.320 m/s² · (4.50 s) ²

    x = - 2.34 m

    The position of the particle is - 2.34 m.
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