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18 March, 20:23

A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6°C. Determine the temperature at which the volume of the gas is 3.45 L.

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  1. 18 March, 21:21
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    281 K

    Explanation:

    Charles's Law. V1/T1 = V2/T2.

    The temperature must be in K = 21.6°C + 273 = 294.6K.

    V1T2 = V2T1.

    3.62L x T2 = 3.45L x 294.6K

    T2 = (3.45 x 294.6) / 3.62 = 1016.4 / 3.62 = B) : 281K.

    (By direct proportion of volume change: (3.45L / 3.62L) x 294.6K = 281K).
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