Sergei tees off on a stationary hockey puck using his most powerful slap shot. If he can exert a force of 250 N on the 500 gram puck for a time of 0.1 seconds, what velocity will he give to it, and how far will the puck move in the time it is on his stick?

Question

Physics

Patterson

17 September, 12:57

Sergei tees off on a stationary hockey puck using his most powerful slap shot. If he can exert a force of 250 N on the 500 gram puck for a time of 0.1 seconds, what velocity will he give to it, and how far will the puck move in the time it is on his stick?

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Answers (1)

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Joslyn Parsons · Answer 1

Answer: velocity = 50m/s

Distance moved=5m

Explanation:

Using the formula Ft=Mv i. e impulse = momentum

Where F = force, t = time, M = mass, v = velocity

In this case we need to find v,

F, t, M are all given in the question.

Therefore, substituting the values we have

250N*0.1s=0.5kg*v. Mass=500g = 0.5kg

v=25/0.5 = 50m/s

The distance the puck will move when it is on his stick.

D = Velocity * time

D=50m/s * 0.1s

D=5m

Goodluck ...