Ask Question
11 October, 12:17

The club was in contact with a ball, initially at rest, for about 0.0052 s. If the ball has a mass of 55 g and leaves the head of the club with a speed of 2.4 ✕ 102 ft/s, find the average force (in kN) exerted on the ball by the club.

+1
Answers (1)
  1. 11 October, 13:16
    0
    2538.46N

    Explanation:

    Parameters given:

    Initial speed, u = 0 m/s

    Final velocity, v = 240 m/s

    Time, t = 0.0052 s

    Mass of club, m = 55g = 0.055 kg

    First we find the acceleration:

    a = (v - u) / t

    a = (240 - 0) / 0.0052

    a = 46153.85 m/s²

    Average force can then be found:

    F = m*a

    F = 0.055 * 46153.85

    F = 2538.46 N
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The club was in contact with a ball, initially at rest, for about 0.0052 s. If the ball has a mass of 55 g and leaves the head of the club ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers