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5 July, 01:47

A helium balloon has an internal pressure of 2.5 atm when it occupies 4.5 L. If it was compressed until it had a pressure of 3.3 atm, what would be the final volume? Report your answer with the correct number of significant figures.

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  1. 5 July, 02:23
    0
    Answer:3.40L

    Explanation:

    p1v1=p2v2

    P1=2.5atm

    V1 = 4.5L

    P2=3.3atm

    V2=?

    P1V1/P2=V2

    V2=2.5*4.5/3.3

    V2 = 11.25/3.3

    V2=3.40L
  2. 5 July, 03:02
    0
    Answer: V = 3.4 L

    Explanation: Use Boyle's Law to find the new volume. P1V1 = P2V2, derive for V2, then the formula will be V2 = P1V1 / P2

    V2 = 2.5 atm (4.5 L) / 3.3 atm

    = 3.4 L
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