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Today, 10:11

A block of material of volume 20cm³ and density of 2.5gcm³suspended from a

spring balance with half of the volume of the block immersed in water. What is the

reading of the spring balance?

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Answers (1)
  1. Today, 10:28
    0
    0.4 N

    Explanation:

    Draw a free body diagram of the block. There are three forces: weight force mg pulling down, buoyancy force ρVg pushing up, and tension force T pulling up.

    Sum of forces in the y direction:

    ∑F = ma

    T + ρVg - mg = 0

    T = mg - ρVg

    T = g (m - ρV)

    Plugging in values:

    T = (9.8 m/s) ((2.5 g/cm³ * 20 cm³) - (1 g/cm³) (10 cm³)) (1 kg / 1000 g)

    T = 0.392 N

    Rounded to one significant figure, the reading of the spring scale is 0.4 N.
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