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30 July, 08:14

The drawings show three situations in which a positively charged particle is moving through a uniform magnetic field B with a velocity v. For each situation, what is the direction of the magnetic force F exerted on the particle?

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  1. 30 July, 09:24
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    Case A: - x axis

    Case B: - x axis

    Case C: no force as the direction of v and B are parallel.

    Explanation:

    Solution:

    - The direction of Force exerted by the magnetic field B with a moving charge q with a velocity of v is given by an expression:

    F = q * (v x B)

    - Where F: force vector exerted by the field

    v: velocity vector of charged particle q.

    B: magnetic field direction

    - The cross product of v with B:

    We will use right hand rule in which our fingers curl from v to B, the direction of the thumb denotes the direction of applied force. Hence,

    Case A: - x axis

    Case B: - x axis

    Case C: no force as the direction of v and B are parallel.
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